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TestAS · Life Sciences

Mathematics and statistics: TestAS practice testlets

Proportions, logarithmic scales, exponential growth and decay, averages and probabilities.

testas.de lists this topic for the Life Sciences module. In the test it comes as testlets: a short text, table or formula, then 4 to 8 questions you answer from it.

Topic list: testas.de

Two practice testlets

Full exam-length testlets from the Kollego course, generated the same way as our mocks. Answer from the material, then open each answer to check.

Testlet 1

Error bars and statistical significance

Biological measurements vary, so results are reported with a measure of spread or uncertainty. Two measures are often shown as error bars in figures, and they must not be confused. The standard deviation (SD) describes how much individual values vary around the mean. The standard error of the mean (SEM) describes how precisely the mean itself has been estimated; it equals the SD divided by the square root of the sample size n. As more data are collected, the SD stays roughly the same, but the SEM shrinks. A figure should always state which measure its error bars show.

SEM = SD ÷ √n approximate 95% confidence interval: mean ± 2 × SEM

A 95% confidence interval gives a range of plausible values for the true mean. For reasonably large samples it extends about two standard errors on either side of the sample mean. If the same study were repeated many times, about 95% of such intervals would contain the true mean.

To decide whether a difference between groups is larger than chance variation would explain, researchers use significance tests, such as the t-test for comparing two means. The test starts from a null hypothesis, usually that there is no real difference. The p-value is the probability of obtaining a difference at least as large as the observed one if the null hypothesis were true. If p is below a threshold chosen in advance, commonly 0.05, the result is called statistically significant. The p-value is not the probability that the null hypothesis is true.

Statistical significance is not the same as importance. With very large samples, tiny differences become significant; with small samples, important effects can be missed. Researchers therefore also report effect sizes and confidence intervals. When many tests are carried out, some will be significant by chance alone: with 20 independent tests of true null hypotheses at the 0.05 level, one false positive is expected on average.

Good practice is to decide on the sample size, the main outcome and the statistical test before collecting the data, and to report all tests that were carried out, not only the significant ones.

Blood pressure reduction after 8 weeks (mmHg)
GroupnMeanSD
New drug1001210
Placebo100510

A t-test comparing the two groups gives p < 0.001.

  1. 1. What is the standard error of the mean for the drug group?

    • a12.0 mmHg
    • b10.0 mmHg
    • c0.1 mmHg
    • d1.0 mmHg
    Show answer

    D: 1.0 mmHg

    SEM = SD ÷ √n. Drug group: SD = 10, n = 100, so SEM = 10 ÷ √100 = 10 ÷ 10 = 1 mmHg.

  2. 2. What is the approximate 95% confidence interval for the mean reduction with the drug?

    • a10 to 14 mmHg
    • b2 to 22 mmHg
    • c11 to 13 mmHg
    • d7 to 17 mmHg
    Show answer

    A: 10 to 14 mmHg

    95% CI ≈ mean ± 2 × SEM = 12 ± 2 × 1 = 12 ± 2, so 10 to 14 mmHg. (12 ± 2 × SD = 2 to 22 would use the wrong measure.)

  3. 3. What does p < 0.001 mean here?

    • aThe drug lowers blood pressure in 99.9% of patients
    • bSuch a large difference would be very unlikely if the drug had no effect
    • cThe difference is less than 0.001 mmHg
    • dThe probability that the drug works for every patient in the trial is over 99.9%
    Show answer

    B: Such a large difference would be very unlikely if the drug had no effect

    By the text, p is the probability of a difference at least this large if the null hypothesis (no real difference) were true. p < 0.001 means such a difference would be very unlikely without a drug effect.

  4. 4. If the drug group had 400 patients with the same SD, what would its SEM be?

    • a1.00 mmHg
    • b0.50 mmHg
    • c0.25 mmHg
    • d2.50 mmHg
    Show answer

    B: 0.50 mmHg

    SEM = SD ÷ √n = 10 ÷ √400 = 10 ÷ 20 = 0.5 mmHg. Four times as many patients halves the SEM.

  5. 5. A figure shows error bars without saying what they are. Why is this a problem?

    • aSD bars are √n times wider than SEM bars
    • bReaders can calculate p from the bars alone
    • cError bars are always the same as the range
    • dError bars never depend on the sample size
    Show answer

    A: SD bars are √n times wider than SEM bars

    SEM = SD ÷ √n, so SD = √n × SEM: SD bars are √n times wider (here √100 = 10 times). Without a label the reader cannot tell which spread is shown.

  6. 6. A lab runs 40 independent tests of substances that in fact have no effect, using p < 0.05. How many significant results are expected by chance?

    • aAbout 0.05
    • bAbout 20
    • cAbout 2
    • dNone
    Show answer

    C: About 2

    If a substance has no effect, each test is significant by chance with probability 0.05 (the text: 1 in 20 tests). For 40 tests: 40 × 0.05 = 2.

Testlet 2

Exponential growth and decay

Many processes in biology change by a constant factor in equal time intervals rather than by a constant amount. A bacterial population that doubles every 30 minutes grows exponentially: after 30 minutes it is twice as large, after one hour four times, after two hours sixteen times. Radioactive substances, drugs in the body and light passing through an absorbing solution decrease exponentially: in each equal interval, the same fraction is lost.

If the doubling time Td is known, the size of a growing population after time t is the initial size N0 multiplied by 2 to the power of t divided by Td. For decay, the half-life T½ takes the place of the doubling time, and the base is one half. Equivalently, exponential change can be written with the natural base e and a rate constant k; the doubling time and k are linked by Td = ln 2 ÷ k, where ln 2 is about 0.693.

growth: N = N0 × 2^(t ÷ Td) decay: N = N0 × (1/2)^(t ÷ T½) Td = ln 2 ÷ k ≈ 0.693 ÷ k

Exponential growth is easy to underestimate. A pond lily that doubles its area every day and covers the whole pond on day 30 covered only half the pond on day 29 and about one thousandth of it on day 20, since 2 to the power of 10 is 1,024. For the same reason, an epidemic that doubles every three days can go from a few cases to overwhelming numbers within weeks.

No real population can grow exponentially for long. As resources run short, growth slows. A bacterial culture in a closed flask passes through a lag phase, in which the cells adapt, an exponential (log) phase, a stationary phase, in which division and death balance, and finally a death phase.

Exponential data are often plotted with a logarithmic vertical axis. On such a semi-logarithmic plot, exponential growth or decay appears as a straight line, which makes it easy to read off doubling times and to spot deviations.

The same mathematics describes money growing at compound interest and the spread of an infection in its early phase. In each case, a useful rule of thumb is that a quantity growing by r percent per time unit doubles in about 70 ÷ r time units.

Bacterial counts in a culture (cells per mL)
Time (h)01234
Count2,0008,00032,000128,000512,000
  1. 1. What is the doubling time of the culture?

    • a1 hour
    • b30 minutes
    • c15 minutes
    • d2 hours
    Show answer

    B: 30 minutes

    In the table the count goes from 2,000 to 8,000 in 1 hour, so × 4. Since 4 = 2 × 2, that is two doublings per hour, so one doubling every 60 ÷ 2 = 30 minutes.

  2. 2. If growth continued unchanged, what would the count be after 5 hours?

    • a1,024,000 per mL
    • b640,000 per mL
    • c4,096,000 per mL
    • d2,048,000 per mL
    Show answer

    D: 2,048,000 per mL

    The count is multiplied by 4 every hour. At 4 hours it is 512,000 per mL, so at 5 hours: 512,000 × 4 = 2,048,000 per mL.

  3. 3. A drug has a half-life of 4 hours. What fraction remains after 12 hours?

    • aOne quarter
    • bOne third
    • cOne eighth
    • dOne twelfth
    Show answer

    C: One eighth

    12 hours ÷ 4 hours = 3 half-lives. Each halves the amount: 1 → 1/2 → 1/4 → 1/8, so one eighth remains.

  4. 4. A population grows with a rate constant k = 0.0693 per day. What is its doubling time?

    • a10.00 days
    • b6.93 days
    • c100.00 days
    • d0.10 days
    Show answer

    A: 10.00 days

    The text gives Td = ln 2 ÷ k ≈ 0.693 ÷ k. With k = 0.0693 per day: 0.693 ÷ 0.0693 = 10 days.

  5. 5. An algal bloom doubles daily and covers a lake completely on day 20. On which day did it cover a quarter of the lake?

    • aDay 15
    • bDay 10
    • cDay 18
    • dDay 5
    Show answer

    C: Day 18

    Going back one day halves the area: day 20 the whole lake, day 19 one half, day 18 one quarter. So a quarter was covered on day 18.

  6. 6. How does exponential growth appear on a plot with a logarithmic vertical axis?

    • aAs a horizontal line
    • bAs an S-shaped curve with a plateau
    • cAs a straight rising line
    • dAs a curve that bends upwards
    Show answer

    C: As a straight rising line

    The text says that on a semi-logarithmic plot exponential growth appears as a straight line; since the count rises, the line rises.

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