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TestAS · Engineering

Mathematics and statistics: TestAS practice testlets

Rearranging formulas, proportions, percentages, simple functions and reading statistical values from tables. The maths is school level; the difficulty is doing it fast and without mistakes.

testas.de lists this topic for the Engineering module. In the test it comes as testlets: a short text, table or formula, then 4 to 8 questions you answer from it.

Topic list: testas.de

Two practice testlets

Full exam-length testlets from the Kollego course, generated the same way as our mocks. Answer from the material, then open each answer to check.

Testlet 1

The square-cube law: scaling up and down

When an object is scaled up or down while keeping its shape, its dimensions do not all change in the same proportion. If every length is multiplied by a scale factor k, every area, such as a surface or a cross-section, is multiplied by k², and every volume is multiplied by k³. Since mass is proportional to volume for a given material, mass also grows with k³. This relationship, known since Galileo, is called the square-cube law.

length × k area × k² volume and mass × k³ stress = force ÷ area ∝ k³ ÷ k² = k

The law has important consequences in engineering and biology. The load on a supporting cross-section, such as a leg, a column or a beam, grows with the weight, that is with k³, while the cross-section itself grows only with k². The stress in the material therefore grows in proportion to k. A statue that is scaled up by a factor of two, using the same material, experiences twice the stress in its legs. Scaled up far enough, any structure would collapse under its own weight, which is why giant animals must have disproportionately thick legs and why there is a limit to the height of buildings made of a given material.

The ratio of surface to volume decreases as objects grow: it is proportional to 1/k. Small objects have a large surface compared with their volume, large objects a small one. This explains why small animals lose heat quickly and must eat a lot relative to their mass, why fine powders burn or dissolve much faster than lumps, and why large engines and large buildings can be more energy-efficient than small ones.

Engineers use scale models in wind tunnels and towing tanks, but must take the square-cube law into account when transferring results to the full-size object. The paint needed for a ship's hull grows with the surface, the displacement of the ship with its volume. The questions refer to a statue and to a model of a ship built at a scale of 1:50, both made of the same materials as the originals. Effects such as the thickness of the paint layer are ignored.

Objects
ObjectData
StatueScaled up by a factor of 2 in every length
Ship model (1:50)Mass 4 kg; hull surface 0.5 m²
  1. 1. By what factor does the mass of the statue increase?

    • a2
    • b6
    • c8
    • d4
    Show answer

    C: 8

    2³.

  2. 2. By what factor does the cross-section of the statue's legs increase?

    • a2
    • b4
    • c8
    • d16
    Show answer

    B: 4

    2².

  3. 3. By what factor does the stress in the statue's legs increase?

    • a4
    • b2
    • c1, since the material is the same
    • d8
    Show answer

    B: 2

    Stress ∝ k: 8 ÷ 4.

  4. 4. What is the mass of the full-size ship, according to the square-cube law?

    • a500,000 kg
    • b5,000 kg
    • c10,000 kg
    • d200 kg
    Show answer

    A: 500,000 kg

    4 kg × 50³ = 4 × 125,000.

  5. 5. How much hull surface must be painted on the full-size ship?

    • a125 m²
    • b1,250 m²
    • c62,500 m²
    • d25 m²
    Show answer

    B: 1,250 m²

    0.5 m² × 50².

  6. 6. An animal is three times as long as a similar animal of the same shape. How does its surface-to-volume ratio compare?

    • aIt is the same
    • bIt is one third as large
    • cIt is one ninth as large
    • dIt is three times as large
    Show answer

    B: It is one third as large

    Surface-to-volume ∝ 1/k.

Testlet 2

Converting units: energy, pressure, flow and speed

Technical data are often given in units that are convenient in practice but not in the base units of the International System of Units (SI). Before calculating, all quantities should be converted into consistent units, usually metres, kilograms, seconds and the units derived from them, such as newtons, joules, watts and pascals. Errors in unit conversion are among the most frequent causes of wrong results, and in a few famous cases they have destroyed entire projects.

A reliable method is to multiply by fractions that equal one. Since 1 hour equals 3,600 seconds, the fraction 1 h ÷ 3,600 s equals one, and multiplying by it changes the unit without changing the quantity. For speeds, this gives the rule that a value in km/h is divided by 3.6 to obtain m/s. For energy, one kilowatt hour is 1,000 watts for 3,600 seconds, which equals 3,600,000 joules or 3.6 megajoules.

1 kWh = 3.6 MJ 1 bar = 100,000 Pa = 100 kPa 1 L = 1 dm³ = 0.001 m³ 1 m/s = 3.6 km/h 1 mm² = 10⁻⁶ m²

Areas and volumes need special care, because the conversion factor is squared or cubed. One metre is 1,000 millimetres, so one square metre is 1,000,000 square millimetres and one cubic metre is 1,000,000,000 cubic millimetres. One litre is one cubic decimetre, a thousandth of a cubic metre. Pressure is often given in bar, especially for tyres and hydraulic systems; one bar equals 100,000 pascals, roughly the air pressure at sea level. Density is often stated in grams per cubic centimetre; since one cubic metre contains a million cubic centimetres and a kilogram is a thousand grams, 1 g/cm³ equals 1,000 kg/m³.

Consumption figures can be expressed in two directions. Fuel consumption in Europe is usually given in litres per 100 kilometres, while in other countries the distance per unit of fuel is used, for example kilometres per litre or miles per gallon. The two are reciprocal: a high value of one means a low value of the other. After converting, a quick plausibility check helps: a result that suggests a car drives at 300 m/s in town or a kettle uses a megawatt hour should be recalculated. Writing the units next to every number in a calculation, and cancelling them like algebraic factors, is the simplest way to catch such mistakes early.

  1. 1. How many megajoules does a 2 kW heater use in 30 minutes?

    • a3.6 MJ
    • b60.0 MJ
    • c7.2 MJ
    • d1.0 MJ
    Show answer

    A: 3.6 MJ

    2 kW × 0.5 h = 1 kWh = 3.6 MJ.

  2. 2. A tyre has a pressure of 2.5 bar. What is this in pascals?

    • a2,500,000 Pa
    • b2,500 Pa
    • c250,000 Pa
    • d25,000 Pa
    Show answer

    C: 250,000 Pa

    2.5 × 100,000 Pa.

  3. 3. A pump delivers 12 litres per minute. What is this in m³/s?

    • a2·10⁻⁴ m³/s
    • b2·10⁻² m³/s
    • c0.72 m³/s
    • d0.2 m³/s
    Show answer

    A: 2·10⁻⁴ m³/s

    12 L/min = 0.2 L/s = 0.0002 m³/s.

  4. 4. A car consumes 6 litres per 100 km. How far does it travel on one litre?

    • aAbout 60 km
    • bAbout 16.7 km
    • cAbout 1.7 km per litre of fuel
    • d6 km
    Show answer

    B: About 16.7 km

    100 km ÷ 6 L.

  5. 5. What is a cross-section of 100 mm² in m²?

    • a10⁻² m²
    • b10⁻⁶ m²
    • c0.1 m²
    • d10⁻⁴ m²
    Show answer

    D: 10⁻⁴ m²

    100 × 10⁻⁶ m².

  6. 6. Steel has a density of 7.8 g/cm³. What is this in kg/m³?

    • a7,800 kg/m³
    • b0.0078 kg/m³
    • c78 kg/m³
    • d780 kg/m³
    Show answer

    A: 7,800 kg/m³

    1 g/cm³ = 1,000 kg/m³.

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PhysicsChemistryMaterialsTechnical mechanicsThermodynamicsElectrical engineeringComputer scienceDevelopment and construction

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