Kollego
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Equations and inequalities

Exponential and log equations

When x sits in the exponent, you either write both sides with the same base or take the logarithm. Log equations work the other way round.

The rules

Practice questions with solutions

Generated by the same engine as the Kollego course and solvable without a calculator. Pick an answer in your head, then open the solution.

  1. 1. Solve for x: 5ˣ = 25

    • a2
    • b1
    • c5
    • d3
    Show solution

    Answer: 2

    Write the right side as a power of the same base, then match exponents.

    25 = 5², so x = 2.

  2. 2. Solve for x: 3ˣ = 243

    • a4
    • b6
    • c3
    • d5
    Show solution

    Answer: 5

    Write the right side as a power of the same base, then match exponents.

    243 = 3⁵, so x = 5.

  3. 3. Solve for x: log₁₀(x) = 5

    • a100010
    • b100000
    • c50
    • d99990
    Show solution

    Answer: 100000

    logₐ(x) = e means x = aᵉ.

    x = 10⁵ = 100000.

  4. 4. Solve for x: log₂(x) = 4

    • a16
    • b14
    • c8
    • d18
    Show solution

    Answer: 16

    logₐ(x) = e means x = aᵉ.

    x = 2⁴ = 16.

  5. 5. Solve for x: log₁₀(x) = 3

    • a990
    • b1000
    • c30
    • d1010
    Show solution

    Answer: 1000

    logₐ(x) = e means x = aᵉ.

    x = 10³ = 1000.

  6. 6. Solve for x: log₃(x) = 5

    • a246
    • b240
    • c15
    • d243
    Show solution

    Answer: 243

    logₐ(x) = e means x = aᵉ.

    x = 3⁵ = 243.

Common mistakes

Related topics

Linear equationsQuadratic equationsHigher-degree equationsSystems of equationsInequalitiesPolynomial divisionRoot equationsAbsolute value equations

All maths topics · T-Kurs · M-Kurs · W-Kurs

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