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Chemistry: TestAS practice testlets

Formulas, reactions, amounts of substance and concentrations, explained in the text and then calculated.

testas.de lists this topic for the MINT (Maths / CS / Natural Sciences) module. In the test it comes as testlets: a short text, table or formula, then 4 to 8 questions you answer from it.

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Two practice testlets

Full exam-length testlets from the Kollego course, generated the same way as our mocks. Answer from the material, then open each answer to check.

Testlet 1

The esterification equilibrium

Many reactions do not run to completion but reach a state of dynamic equilibrium, in which the forward and reverse reactions proceed at the same rate. The concentrations of all substances then remain constant, although reactions continue at the particle level. A classic example is esterification, the reaction of a carboxylic acid with an alcohol to form an ester and water. Esters are responsible for the smell of many fruits and are used as solvents and flavourings.

acetic acid + ethanol ⇌ ethyl acetate + water K = [ester]·[water] ÷ ([acid]·[alcohol])

The position of the equilibrium is described by the equilibrium constant K, which relates the concentrations of products and reactants at equilibrium. For the esterification of acetic acid with ethanol, K is about 4 at room temperature. If one mole each of acid and alcohol are mixed in a given volume and x moles of ester are formed, then x moles of water are also formed, and 1 − x moles each of acid and alcohol remain. Setting x² ÷ (1 − x)² = 4 gives x ÷ (1 − x) = 2, and so x = 2/3: at equilibrium, two thirds of the acid have been converted into ester. The reaction is slow, and a few drops of concentrated sulphuric acid are added as a catalyst.

Le Chatelier's principle predicts how an equilibrium responds to disturbances: the system shifts so as to counteract the change. Adding more of one reactant, for example an excess of the cheaper alcohol, shifts the equilibrium towards the products and increases the yield of ester relative to the acid. Removing a product, for example by distilling off the ester or binding the water, also shifts the equilibrium to the right. A catalyst, by contrast, speeds up both the forward and the reverse reaction equally: equilibrium is reached faster, but its position does not change.

The reverse reaction, the splitting of an ester by water, is called hydrolysis. In the presence of a base such as sodium hydroxide, the acid formed is converted into its salt and removed from the equilibrium, so the hydrolysis runs almost to completion. This reaction, applied to fats, which are esters of glycerol and fatty acids, is the basis of soap-making and is known as saponification. Soaps are therefore the salts of fatty acids.

  1. 1. What characterises a dynamic equilibrium?

    • aOnly the forward reaction takes place
    • bForward and reverse reactions proceed at the same rate
    • cAll reactions have stopped completely
    • dThe concentrations of reactants and products are always equal
    Show answer

    B: Forward and reverse reactions proceed at the same rate

    Concentrations are constant, but reactions continue.

  2. 2. One mole each of acetic acid and ethanol react (K = 4). How much ester is present at equilibrium?

    • a1 mol
    • b2/3 mol
    • c1/2 mol
    • d4/5 mol
    Show answer

    B: 2/3 mol

    x ÷ (1 − x) = 2.

  3. 3. How much acetic acid remains at equilibrium in that case?

    • a1/3 mol
    • b1/4 mol
    • c2/3 mol
    • dNone, since the acid reacts completely
    Show answer

    A: 1/3 mol

    1 − 2/3.

  4. 4. How can the yield of ester relative to the acid be increased?

    • aBy adding more sulphuric acid as catalyst
    • bBy adding more water
    • cBy adding more of the ester at the start
    • dBy adding an excess of ethanol
    Show answer

    D: By adding an excess of ethanol

    Le Chatelier's principle.

  5. 5. What is the effect of the sulphuric acid catalyst on the equilibrium?

    • aIt is reached faster, but its position does not change
    • bIt shifts the equilibrium towards the ester
    • cIt shifts the equilibrium towards the acid
    • dIt increases the equilibrium constant from 4 to a higher value
    Show answer

    A: It is reached faster, but its position does not change

    Both directions are accelerated equally.

  6. 6. Why does ester hydrolysis with sodium hydroxide run almost to completion?

    • aEsters do not form an equilibrium with water
    • bSodium hydroxide is a catalyst that shifts the equilibrium
    • cThe equilibrium constant of hydrolysis with a base is exactly 4
    • dThe acid formed is converted into its salt and removed from the equilibrium
    Show answer

    D: The acid formed is converted into its salt and removed from the equilibrium

    Saponification.

Testlet 2

The pH scale and buffer solutions

In aqueous solutions, acids release hydrogen ions (protons), which combine with water molecules to form oxonium ions, H₃O⁺. The acidity of a solution is expressed by its pH value, the negative decimal logarithm of the oxonium ion concentration in mol/L. A solution with [H₃O⁺] = 0.01 mol/L = 10⁻² mol/L has a pH of 2. Because the scale is logarithmic, a difference of one pH unit corresponds to a factor of ten in concentration: a solution of pH 3 contains ten times fewer oxonium ions than one of pH 2.

pH = −lg [H₃O⁺] [H₃O⁺] = 10⁻ᵖᴴ neutral at 25 °C: pH 7 pH + pOH = 14

Pure water at 25 °C has a pH of 7; acidic solutions have lower values, basic (alkaline) solutions higher values. Strong acids such as hydrochloric acid dissociate almost completely, so the oxonium ion concentration equals the acid concentration. Weak acids such as acetic acid dissociate only partly, so a solution of the same concentration has a higher pH. Diluting a strong acid tenfold with water raises its pH by one unit; however, no amount of dilution can make an acid solution basic, since the pH approaches 7 but does not exceed it.

A buffer solution resists changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base in similar amounts, for example acetic acid and sodium acetate. Added oxonium ions are taken up by the acetate ions, forming acetic acid; added hydroxide ions react with acetic acid, forming acetate and water. The pH therefore changes only slightly. A buffer works best when the acid and its conjugate base are present in equal concentrations; the pH is then equal to the pKa of the acid, 4.76 for acetic acid.

Buffers are vital in living organisms. Human blood is kept within a narrow range around pH 7.4, mainly by the carbonic acid–hydrogen carbonate buffer system; values below 7.35 or above 7.45 are dangerous. Buffers are also used in laboratories, in the food industry and in cosmetics. When the buffer capacity is exhausted, because one of its components has been used up, the pH changes sharply. The capacity is larger the higher the concentrations of the two buffer components, so a concentrated buffer can absorb more acid or base than a dilute one of the same pH.

  1. 1. What is the pH of a hydrochloric acid solution with [H₃O⁺] = 0.001 mol/L?

    • a1.000
    • b3.000
    • c0.001
    • d−3.000
    Show answer

    B: 3.000

    −lg 10⁻³.

  2. 2. A solution of pH 2 is compared with one of pH 4. How do their oxonium ion concentrations compare?

    • aThe pH 2 solution has 20 times more
    • bThe pH 2 solution has 100 times more
    • cThe pH 2 solution has twice as much
    • dThe pH 4 solution has 100 times more
    Show answer

    B: The pH 2 solution has 100 times more

    Two units, factor 10².

  3. 3. A strong acid of pH 1 is diluted tenfold with water. What is the new pH?

    • a2
    • b7
    • c10
    • d0
    Show answer

    A: 2

    Tenfold dilution raises the pH by one unit.

  4. 4. Why does a weak acid have a higher pH than a strong acid of the same concentration?

    • aIt is a buffer by itself
    • bIt contains fewer hydrogen atoms
    • cIt reacts with water to form hydroxide ions only
    • dIt dissociates only partly
    Show answer

    D: It dissociates only partly

    Fewer oxonium ions are formed.

  5. 5. What happens when a small amount of acid is added to an acetate buffer?

    • aAcetate ions take up the added oxonium ions
    • bThe pH drops sharply by several units
    • cAcetic acid releases more oxonium ions
    • dThe buffer turns basic because of the sodium ions it contains
    Show answer

    A: Acetate ions take up the added oxonium ions

    Acetic acid is formed.

  6. 6. An acetate buffer contains equal concentrations of acetic acid and acetate. What is its pH?

    • a7.40
    • b7.00
    • c2.38
    • d4.76
    Show answer

    D: 4.76

    pH = pKa when the ratio is 1:1.

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